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Java Program to check for a Magic Number

This is a Java program for Magic number. However before starting let me tell you what is a magic number.

A Magic number is a number whose sum of digits eventually leads to 1.
Example#1:  19 ;  1+9 =10 ; 1+0 = 1.  Hence a magic number.
Example#2:  226; 2+2+6=10; 1+0 =1.  Hence a magic number.
Example#3:  874; 8+7+4=19; 1+9=10; 1+0=1.  Hence a magic number.

ALSO CHECK: Java program to print the magic number series

class magicno
public static void main(String args[])throws Exception
int i,j;
magicno obj=new magicno();             //creating an object for the class to access the function magic.
BufferedReader br = new BufferedReader(new InputStreamReader(;
System.out.println("enter a number");
i=Integer.parseInt(br.readLine());   // Accept a number from user to check if it is a magic number or not
while((j=obj.magic(i))/10!=0)       //   You have to check the sum of all digits until a single digit is achieved i.e. sum=1,2,3,..9
i=j;				// If sum of digits= 19 it then again goes to 1+9 =10 and again 1+0= '1' a single digit to check 1 or not
if ( j==1)        // check if the single digit is 1 then a magic number else not
System.out.println("It is a magic number ");
System.out.println("Not a magic number");

int magic(int n)
return n;
return n%10+ magic(n/10);   // recursive function that gives last digit for every recursion and adds the returned number to previous value.


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  1. It was very helpful.

  2. It was very helpful

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